Optimal. Leaf size=110 \[ \frac{b \tan ^3(e+f x) \sqrt{b \tan ^4(e+f x)}}{5 f}-\frac{b \tan (e+f x) \sqrt{b \tan ^4(e+f x)}}{3 f}-b x \cot ^2(e+f x) \sqrt{b \tan ^4(e+f x)}+\frac{b \cot (e+f x) \sqrt{b \tan ^4(e+f x)}}{f} \]
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Rubi [A] time = 0.0419221, antiderivative size = 110, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.214, Rules used = {3658, 3473, 8} \[ \frac{b \tan ^3(e+f x) \sqrt{b \tan ^4(e+f x)}}{5 f}-\frac{b \tan (e+f x) \sqrt{b \tan ^4(e+f x)}}{3 f}-b x \cot ^2(e+f x) \sqrt{b \tan ^4(e+f x)}+\frac{b \cot (e+f x) \sqrt{b \tan ^4(e+f x)}}{f} \]
Antiderivative was successfully verified.
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Rule 3658
Rule 3473
Rule 8
Rubi steps
\begin{align*} \int \left (b \tan ^4(e+f x)\right )^{3/2} \, dx &=\left (b \cot ^2(e+f x) \sqrt{b \tan ^4(e+f x)}\right ) \int \tan ^6(e+f x) \, dx\\ &=\frac{b \tan ^3(e+f x) \sqrt{b \tan ^4(e+f x)}}{5 f}-\left (b \cot ^2(e+f x) \sqrt{b \tan ^4(e+f x)}\right ) \int \tan ^4(e+f x) \, dx\\ &=-\frac{b \tan (e+f x) \sqrt{b \tan ^4(e+f x)}}{3 f}+\frac{b \tan ^3(e+f x) \sqrt{b \tan ^4(e+f x)}}{5 f}+\left (b \cot ^2(e+f x) \sqrt{b \tan ^4(e+f x)}\right ) \int \tan ^2(e+f x) \, dx\\ &=\frac{b \cot (e+f x) \sqrt{b \tan ^4(e+f x)}}{f}-\frac{b \tan (e+f x) \sqrt{b \tan ^4(e+f x)}}{3 f}+\frac{b \tan ^3(e+f x) \sqrt{b \tan ^4(e+f x)}}{5 f}-\left (b \cot ^2(e+f x) \sqrt{b \tan ^4(e+f x)}\right ) \int 1 \, dx\\ &=\frac{b \cot (e+f x) \sqrt{b \tan ^4(e+f x)}}{f}-b x \cot ^2(e+f x) \sqrt{b \tan ^4(e+f x)}-\frac{b \tan (e+f x) \sqrt{b \tan ^4(e+f x)}}{3 f}+\frac{b \tan ^3(e+f x) \sqrt{b \tan ^4(e+f x)}}{5 f}\\ \end{align*}
Mathematica [A] time = 0.735057, size = 66, normalized size = 0.6 \[ \frac{\cot (e+f x) \left (b \tan ^4(e+f x)\right )^{3/2} \left (15 \cot ^4(e+f x)-5 \cot ^2(e+f x)-15 \tan ^{-1}(\tan (e+f x)) \cot ^5(e+f x)+3\right )}{15 f} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.016, size = 64, normalized size = 0.6 \begin{align*} -{\frac{-3\, \left ( \tan \left ( fx+e \right ) \right ) ^{5}+5\, \left ( \tan \left ( fx+e \right ) \right ) ^{3}+15\,\arctan \left ( \tan \left ( fx+e \right ) \right ) -15\,\tan \left ( fx+e \right ) }{15\,f \left ( \tan \left ( fx+e \right ) \right ) ^{6}} \left ( b \left ( \tan \left ( fx+e \right ) \right ) ^{4} \right ) ^{{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.57448, size = 72, normalized size = 0.65 \begin{align*} \frac{3 \, b^{\frac{3}{2}} \tan \left (f x + e\right )^{5} - 5 \, b^{\frac{3}{2}} \tan \left (f x + e\right )^{3} - 15 \,{\left (f x + e\right )} b^{\frac{3}{2}} + 15 \, b^{\frac{3}{2}} \tan \left (f x + e\right )}{15 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.45319, size = 163, normalized size = 1.48 \begin{align*} \frac{{\left (3 \, b \tan \left (f x + e\right )^{5} - 5 \, b \tan \left (f x + e\right )^{3} - 15 \, b f x + 15 \, b \tan \left (f x + e\right )\right )} \sqrt{b \tan \left (f x + e\right )^{4}}}{15 \, f \tan \left (f x + e\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b \tan ^{4}{\left (e + f x \right )}\right )^{\frac{3}{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 4.77166, size = 1457, normalized size = 13.25 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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